Examples for lenses
Example #1
Problem:
a.) A converging lens (concave) has a focal length of 14 cm. Looking through the lens, one sees an image 20 cm behind the lens. Where is the object?
Solution:
Since the image is behind the lens, it is virtual and the distance di is negative. Using the formula, , one can solve for do.
do = 8.24 cm
b.) If the height of the object is 1.5 cm, what is the height of the image.
Solution:
Using the formula, to get
hi = 3.64 cm, upright
Example #2
Problem:
A real image of a coin is observed 34 cm beyond a lens. The image height is 1.4 cm and it is known that the actual coin is 0.7 cm high. What is the focal length of the lens?
Solution:
First, find the object distance using . Remember that since the image is real, that the image height is negative. ( do = 17 cm ). One can then use to find the focal length.
do = 11.33 cm