Physics 321 -- Spring 2004

Homework #4, due at beginning of class Wednesday Feb. 11.

1.         [3pts] Marion & Thornton, problem 9-40.
Hint: Read pg. 364 carefully.  The component of velocity parallel to the surface is unchanged by the collision.  The perpendicular component is not only reversed, but is reduced according to the coefficient of restitution.

2.         [4pts] Consider a one-dimensional (head-on) elastic collision between a particle of mass m1 traveling initially with velocity u1, incident on a particle of mass m2 initially at rest.
(a) Analyze this problem using the center of mass frame of reference.  First, find the initial velocities in the CM frame, u1’ and u2’.  Second, find the final velocities in the CM frame, v1’ and v2’.  Third, transform those final velocities back to the lab frame to get v1 and v2. 
(b) Check that your answers obey conservation of momentum and kinetic energy in the lab frame. (You could have done the whole problem in the lab frame to begin with, but the algebra is easier using the CM frame, and the physics is clearer.)

3.         [4pts] Marion & Thornton, problem 9-34.
Hint: There are solutions both for alpha > 0 and for alpha < 0.

4.         [5pts] Marion & Thornton, problem 9-41.
Hint: After you have written down the two components of conservation of momentum and the relation between initial and final kinetic energy, you have some serious algebra to do. A good approach is to begin by eliminating the unknown angle by using cos2z + sin2z = 1. This leaves only two equations; you can solve them and then plug back into one of the original equations to find the desired angle. (You may prefer to use Mathematica or one of its competitors in place of hand tools for this.)

5.         [4pts] Marion & Thornton, problem 9-42.
(Assume the diameter of the initial coil is negligibly small, so the rope is vertical and angular momentum can be ignored.)

6.         [4pts] Marion & Thornton, problem 9-19.
Hint: You can use Newton’s 2nd Law for the center of mass motion. The motion itself is simple: assume that the links of the chain fall freely when they are above the table, and that they stop without bouncing when they reach it.

7.         [6pts] In class, we solved for the motion of a chain that was initially hanging over the edge of a frictionless horizontal surface. Generalize that problem by assuming that the surface slopes downward toward the edge at an angle theta, and has a coefficient of friction mu. As in the original problem, assume that there is a frictionless barrier in place to keep the part of the chain that is off the table vertical.
(a) Apply Newton's 2nd Law to the vertical part of the chain, to relate the tension at the corner to the acceleration.
(b) Apply Newton's 2nd Law to the part of the chain that is still on the surface, to relate the tension at the corner to the acceleration.
(c) Equate your results from parts (a) and (b) to find the equation of motion of the chain.
(d) Calculate the work done by friction during the time that the length of chain hanging over increases from x0 to x.
(e) Calculate the gravitational potential energy as a function of x.
(f) Use your results from parts (d) and (e) to write a conservation-of-energy equation.
(g) Take the time derivative of your result from part (f) to obtain the equation of motion. If it doesn't agree with your result from part (c), go back and find the mistake!
(h) Solve the equation of motion, assuming the chain starts from rest with a length x0 hanging down.
(i) Check that your answer to (h) is correct in the limit that the angled surface becomes vertical.

(Last updated 2/9/2004.)