The law of reflection can be understood by either the particle picture (think of an elastic collision of a particle with a hard surface) or in terms of waves (Use Huygen's principle). Note that at any interface, there is partial transmission, partial absorption and partial reflection. We shall not discuss absorption much. Optical materials are those which transmit most of the incident light, for these materials obsorption is considered a deleterious effect or a ``loss". Ideal mirrors have perfect reflection while perfect lenses have perfect transmission.
From the formula v = c/n, it is evident
that light waves slow down inside materials.
However if a source is emitting at frequency
f, this frequency should be observed no matter
where a observer is. Another way of stating this
is that the number of wavefronts which pass
an observer per unit time must be the same
as the number of wavefronts produced by the
source, per unit time. The frequency of
light is thus the same inside a material as it is in air.
If the frequency is constant, we have,
(1) |
(2) |
An extremely useful approach to
geometrical optics is to use ray
tracing. The ray associated with
an EM wave is drawn perpendicular to the
wavefronts for the wave. Almost
everything that we shall do in
geometrical optics is most easily
understood using ray tracing. The key principle
concerning rays in geometrical optics is
Fermat's principle which states that: Light rays take the path which has the
shortest transit time. Using this principle
it is easy to prove the laws of reflection
and refraction.
Total internal reflection
An important special case of Snell's law of refraction
is that when light inside a material with refractive
index n1 strikes an interface with refractive
index n2<n1 at a sufficiently high angle, then
reflection occurs instead of transmission. The condition
for this "total internal reflection" is,
(3) |
(4) |
Another extremely important example is
optical fibers. The simplest optical fibers
consist of an inner region(core) of higher
refractive index and an outer region(cladding)
of lower refractive index. Light enters the
fiber at high angles (in a cone of acceptance)
and propagates along the fiber by internal
reflection. Optical communications systems
consist of: Solid state lasers
which produces light from incoming electrical
signals; A network of optical fibers which carries
the signal to the target locations; Photodiodes
which take incoming light and produce electrical
signals from it. Optical fiber communications
networks have many advantages over wireless
communications.
Faraday cage
It is important in some situations to
screen out EM fields. This is achieved by
placing a wire mesh around whatever needs
to be protected. Actually any conducting
surface will do provided the holes in the
mesh are smaller than the wavelength of light
which we wish to screen out.
Polarization
So far we have considered light
which is linearly polarized. We have taken the
electric field as being oscillatory in the x-direction.
Now imagine placing a grid of straight conducting wires
in the path of this wave. If the wires are oriented
in the same direction as the electric field, a current
is induced in the wire and the electric field is
dissipated by these eddy currents. In quantum terminology
the light is absorbed. However if the wires
are oriented in the direction perpendicular to the electric field,
there is little motion of the charges in the wire and hence
the light can propagate through the wires. Polaroid glasses
work in the same way. They are made of molecular wires,
which are long conducting molecules oriented in one
direction. The orientation of the molecules in polaroid
glasses is determined by the properties of
polarization under reflection, which we will
come to a little later.
Malus's law
First consider a polarizer (i.e. the
wires) to be at an angle
to the direction of the
linearly polarized light. We may then write,
this is originally due to Malus,
(5) |
(6) |
Polarizers in series
An amusing feature of Malus's law, is that
two polarizers at 90o to each other will
block light, but if we place a third
polarizer at 45o in between, light
is transmitted, so that even though I2=0,
we have,
(7) |